Spontaneity
·
Changes for which
the products are more stable than the reactants are said to be product favored
or spontaneous.
·
Changes for which
the products are less stable than the reactants are said to be reactant favored
or non-spontaneous.
·
Spontaneity can
vary based on reaction conditions (T, P, etc.)
·
Spontaneity is
favored when:
1.
Heat is released
during the change (exothermic)
2.
The change
results in an increase in disorder (entropy increases)
·
Second Law of
Thermodynamics: in spontaneous changes, the universe tends toward a state of
greater disorder.
Entropy
·
Entropy is a
thermodynamic state function which measures the degree of disorder of the
system
·
Solids are more
ordered than liquids; liquids are more ordered than gases
·
Mixing together
two substances increases the entropy of each.
·
DS universe
= DS system + DS surroundings
·
During a process
the entropy of the system can increase or decrease, but the entropy of the
universe must increase. (If entropy of system decreases, entropy of
surroundings increases.)
·
Third Law of
Thermodynamics: the entropy of a pure, perfect crystalline substance is zero at
absolute zero (0 K)
·
Absolute entropy
values (shown in Appendix 4) take into consideration the temperature of the
system (units = J/mol·K);
T= 298 K.
·
As temperature
increases, so does the disorder of the system
·
Hess’s Law can be
used to calculate entropy changes
DS°rxn = å n S° (products)
- å n S° (reactants)
·
Calculate DS°rxn for
the following reaction.
2 NO (g) + H2
(g) à N2O (g) + H2O (g)
Predictions
for the sign of DS sys can be made:
1.
Phase changes:
melting, vaporization, and sublimation all have DS sys >
0. Reverse processes have DS sys < 0.
2.
T change:
increases in T have DS sys > 0; decrease in
T have DS sys < 0.
3.
V change:
increases in V have DS sys > 0; decrease in
V have DS sys < 0.
4.
Mixing of
substances: substance which become more mixed have DS sys > 0; decreases in mixing lead to DS sys < 0. Dissolving is an example of mixing.
5.
Increase in
number of particles: increases have DS sys >
0; decreases have DS sys < 0.
6.
Changes in number
of moles of gaseous substances: increases have DS sys >
0; decreases have DS sys < 0.
(ex. 2 H2 (g) + O2 (g)
à 2 H2O (g))
Free Energy Change (DG)
The relationship between
enthalpy and entropy was described by J. Willard Gibbs in terms of a new state
function referred to as Gibbs Free Energy (G).
G = H – TS
·
At constant T and
P, DG = DH – TDS
·
A decrease in
Gibbs free energy relates to the release of energy
·
The amount of a
decrease corresponds to the maximum amount of energy available to do work.
·
The value of DG also indicates degree of spontaneity for a reaction.
DG > 0 … rxn is
non-spontaneous (reverse would be spontaneous)
DG = 0 … system is at
equilibrium
DG < 0 … rxn is
spontaneous (reverse would be non-spontaneous)
·
DG becomes more negative as DH becomes more negative (rxn gives off heat) and as DS becomes more positive (disorder increases)
·
Standard states
for temperature and pressure for DG are 1 atm and 25° C.
·
Standard molar
free energy of formation DG°f – the
amount of free energy released when compounds are formed from their
elements. Values are given in Appendix 4.
·
These values can
be used to determine free energy changes for reactions at 1 atm
& 298 K:
DG°rxn = å n DG°f (products)
- å n DG°f (reactants)
·
This allows us to
predict whether reactants or products are more stable under standard conditions
(for the “standard reaction”).
·
DG will vary with conc., T, and P. DG° does not because these conditions cannot vary.
·
In the standard
reaction, all reactants are assumed to be completely converted to products; in
actual reactions an equilibrium is more likely to
occur.
·
DG° can be estimated by the following equation: DG° = DH° - TDS°
·
This is an
estimate because actual values for DH° and DS° will vary somewhat with temperature
Calculate the standard free
energy change for the following reaction at 25°C and 1 atm.
3
NO2 (g) + H2O (l) à 2 HNO3 (l)
+ NO (g)
Use
standard enthalpy of formation and absolute entropy values to estimate DG°
This method can be used
to help estimate the temperature at which a process is at equilibrium.
·
At equilibrium
conditions, DG = 0
·
When DG = 0 the equation DG = DH - TDS can be rearranged to produce:
T = DH/DS
Estimate the normal
condensation point of water at 1 atm.
H2O
(g) à H2O (l)
DH =
DS =
T =
Reactions can be grouped
into four classes
1.
DH < 0 and DS > 0 … both
favorable so rxn is spontaneous.
2.
DH < 0 and DS < 0 … rxn is
spontaneous below a certain T. (DG = DH – TDS)
3.
DH > 0 and DS > 0 … rxn is
spontaneous above a certain T. (DG = DH – TDS)
4.
DH > 0 and DS < 0 … neither
favorable so rxn is non-spontaneous.